A=x^2-10x+300

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Solution for A=x^2-10x+300 equation: 



=A^2-10A+300

We move all terms to the left:

-(A^2-10A+300)=0

We get rid of parentheses

-A^2+10A-300=0

We add all the numbers together, and all the variables

-1A^2+10A-300=0

a = -1; b = 10; c = -300;
Δ = b2-4ac
Δ = 102-4·(-1)·(-300)
Δ = -1100
Delta is less than zero, so there is no solution for the equation

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